A particle has initial velocity (3î + 4ĵ) and has acceleration (0.4î + 0.3ĵ). Its speed after 10 s is

Question

Question

Answer 1

CONCEPT:

Velocity:

The rate of change of displacement of a body is called the velocity of that body.
It is a vector quantity that has both magnitudes as well as direction.

Where S2 is the final displacement at time t2 and S1 is the initial displacement at time t1.

Acceleration:

Where v2 = Final velocity and v1 = Initial velocity of an object at the time respectively

CALCULATION:

Given:

Initial velocity (U) = (3î + 4ĵ), Acceleration (a) = (0.4î + 0.3ĵ), and time (t) =10s

The relationship final velocity (V), Initial velocity (U), and acceleration (a) is given by kinematic equations for the uniformly accelerated motion:

⇒ V = U + at -----(1)

⇒V = (3î + 4ĵ) + (0.4î + 0.3ĵ) × 10 = (3î + 4ĵ) + (4î + 3ĵ) = 7î + 7ĵ