Question
Download Solution PDFA man and his wife appear in an interview for two vacancies in the same post. The probability of husband's selection is (2/7) and the probability of wife's selection is (3/5). What is the probability that only one of them is selected?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCalculation:
The probability of man gets select = \(2\over7\)
The probability of man does not get select = \(1-{2\over7}\) = \(5\over7\)
The probability of woman gets select = \(3\over5\)
The probability of woman does not get select = \(1-{3\over5}\) = \(2\over5\)
The probability that only one gets to select (P):
= [Man gets selected × woman does not get select + Man does not get select × woman get selected]
= \({2\over7}×{2\over5}+{5\over7}×{3\over5}\)
P = \({4\over35}+{15\over35}\) = \(19\over35\)
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