A card is drawn at random from an ordinary deck of 52 playing cards. The probability that the card is a 10 or a spade is:

  1. \(\rm \dfrac{17}{52}\)
  2. \(\rm \dfrac{7}{39}\)
  3. \(\rm \dfrac{4}{13}\)
  4. \(\rm \dfrac{3}{13}\)

Answer (Detailed Solution Below)

Option 3 : \(\rm \dfrac{4}{13}\)
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Detailed Solution

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Concept:

  • The probability of occurrence of an event A out a total possible outcomes N, is given by P(A) = \(\rm \dfrac{n(A)}{N}\), where n(A) is the number of ways in which event A can occur.
  • For two events A and B we have P(A ∪ B) = P(A) + P(B) - P(A ∩ B).

 

Calculation:

Let's say that A is the event of drawing a 10 and B be the event of drawing a spade.

Probability of drawing a 10 = P(A) = \(\rm \dfrac{4}{52}\).

Probability of drawing a spade = P(B) = \(\rm \dfrac{13}{52}\).

Probability of drawing a 10 of spade = P(A ∩ B) = \(\rm \dfrac{1}{52}\).

∴ Probability of drawing a 10 or a spade = P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

\(\rm \dfrac{4}{52}+\dfrac{13}{52}- \dfrac{1}{52}=\dfrac{16}{52}=\dfrac{4}{13}\).

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