Question
Download Solution PDFA can complete a piece of work in 25 days while B can complete the same work in 30 days. They work on alternate basis, starting with A. Both A and B follow this pattern for 5 days and then A leaves the work. In how many days will B finish the remaining work?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
A and B can complete the work in 25 days and 30 days.
A and B work alternatively = 5 days
Formula used:
Work = Efficiency × Time
Calculation:
Total work = LCM of (25, 30)
Total work = 150 unit
The efficiency of A = 150/25 = 6 unit/day
The efficiency of B = 150/30 = 5 unit/day
A and B work alternatively for 5 days, starting with A, then
⇒ 6 × 3 + 5 × 2
= 28 unit
Remaining work = 150 - 28
Remaining work = 122
The Time taken by B to complete the remaining work = 122/5
= 24(2/5) days
∴ The required days to complete the remaining work by 'B' are 24(2/5) days.
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