A body is loaded elastically so that strain in y-direction (ey) = 0 and σz = 0. Take σx and σy as finite. What is the value of strain in z-direction (ez) in terms of stress in x-direction (σx), Young's Modulus (E), and Poisson's ratio (v)?

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UPSC ESE (Prelims) Civil Engineering 19 Feb 2023 Official Paper
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  1. e= σxv(1 + 2v)/E
  2. eσxv(1 - 4v)/E
  3. eσx(1 + v)/E
  4. e= -σxv(1 + v)/E

Answer (Detailed Solution Below)

Option 4 : e= -σxv(1 + v)/E
Free
ST 1: UPSC ESE (IES) Civil - Building Materials
20 Qs. 40 Marks 24 Mins

Detailed Solution

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Explanation:

Concept:

Calculation:

As we know,

Strain in y-direction 

where σx, σy and σz are normal stresses in x, y and z-directions.

So, 

Now, strain in z-direction, 

using above relation         

 or e= -σxv(1 + v)/E { where μ = v}

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