Data Interpretation MCQ Quiz - Objective Question with Answer for Data Interpretation - Download Free PDF
Last updated on Jun 18, 2025
Latest Data Interpretation MCQ Objective Questions
Data Interpretation Question 1:
Comprehension:
Read the given passage and answer the questions that follow
The following table has the number of enrolled students for a particular course and year.
Total number of seats are given in brackets with respect to each course.
Year |
Number of Enrolled Students |
|||
BTech |
MTech |
MPhil |
MBA (60) |
|
2016 | 96 | 24 | 12 | 52 |
2017 | 110 | 26 | 14 | 57 |
2018 | 108 | 25 | 13 | 54 |
2019 | 112 | 28 | 15 | 56 |
2020 | 104 | 27 | 16 | 48 |
Which year has the minimum vacant seats?
Answer (Detailed Solution Below)
Data Interpretation Question 1 Detailed Solution
Given:
Year |
Number of Enrolled Students |
||||
BTech |
MTech |
MPhil |
MBA (60) |
Total (230) |
|
2016 | 96 | 24 | 12 | 52 | 180 |
2017 | 110 | 26 | 14 | 57 | 207 |
2018 | 108 | 25 | 13 | 54 | 200 |
2019 | 112 | 28 | 15 | 56 | 211 |
2020 | 104 | 27 | 16 | 48 | 195 |
Formula Used:
Total Seats = Enrolled Seats + Vacant Seats
Calculation:
Vacant seats in 2016 = 230 - 180 = 50
Vacant seats in 2017 = 230 - 207 = 23
Vacant seats in 2018 = 230 - 200 = 30
Vacant seats in 2019 = 230 - 211 = 19
Vacant seats in 2020 = 230 - 195 = 35
∴ Year which has the minimum vacant seats is 2019
Data Interpretation Question 2:
Comprehension:
Read the given passage and answer the questions that follow
The following table has the number of enrolled students for a particular course and year.
Total number of seats are given in brackets with respect to each course.
Year |
Number of Enrolled Students |
|||
BTech |
MTech |
MPhil |
MBA (60) |
|
2016 | 96 | 24 | 12 | 52 |
2017 | 110 | 26 | 14 | 57 |
2018 | 108 | 25 | 13 | 54 |
2019 | 112 | 28 | 15 | 56 |
2020 | 104 | 27 | 16 | 48 |
Which course has the highest percentage increase in enrollment of students from 2016-2017?
Answer (Detailed Solution Below)
Data Interpretation Question 2 Detailed Solution
Given:
Year |
Number of Enrolled Students |
||||
BTech |
MTech |
MPhil |
MBA (60) |
Total (230) |
|
2016 | 96 | 24 | 12 | 52 | 180 |
2017 | 110 | 26 | 14 | 57 | 207 |
2018 | 108 | 25 | 13 | 54 | 200 |
2019 | 112 | 28 | 15 | 56 | 211 |
2020 | 104 | 27 | 16 | 48 | 195 |
Percentage increase in enrollment of students from 2016-2017 is
In BTech = [(110 - 96)/96] × 100 = (14/96) × 100 = 14.58%
In MTech = [(26 - 24)/24] × 100 = (2/24) × 100 = 8.33%
In MPhil = [(14 - 12)/12] × 100 = (2/12) × 100 = 16.66%
In MBA = [(57 - 52)/52] × 100 = (5/52) × 100 = 9.61%
∴ The course which has the highest percentage increase in enrollment of students from 2016-2017 is MPhil.
Data Interpretation Question 3:
Comprehension:
Read the given passage and answer the questions that follow
The following table has the number of enrolled students for a particular course and year.
Total number of seats are given in brackets with respect to each course.
Year |
Number of Enrolled Students |
|||
BTech |
MTech |
MPhil |
MBA (60) |
|
2016 | 96 | 24 | 12 | 52 |
2017 | 110 | 26 | 14 | 57 |
2018 | 108 | 25 | 13 | 54 |
2019 | 112 | 28 | 15 | 56 |
2020 | 104 | 27 | 16 | 48 |
What is the average number of vacant seats of B. Tech for years (2016-2020)?
Answer (Detailed Solution Below)
Data Interpretation Question 3 Detailed Solution
Given:
Year |
Number of Enrolled Students |
||||
BTech |
MTech |
MPhil |
MBA (60) |
Total (230) |
|
2016 | 96 | 24 | 12 | 52 | 180 |
2017 | 110 | 26 | 14 | 57 | 207 |
2018 | 108 | 25 | 13 | 54 | 200 |
2019 | 112 | 28 | 15 | 56 | 211 |
2020 | 104 | 27 | 16 | 48 | 195 |
Calculation:
The number of vacant seats of B.Tech for years (2016-2020) is
In the year 2016 = 120 - 96 = 24
In the year 2017 = 120 - 110 = 10
In the year 2018 = 120 - 108 = 12
In the year 2019 = 120 - 112 = 8
In the year 2020 = 120 - 104 = 16
So, the average number of vacant seats of B. Tech for years (2016-2020) is
⇒ (24 + 10 + 12 + 8 + 16)/5
⇒ 70/5 = 14
∴ The average number of vacant seats of B. Tech for years (2016 - 2020) is 14
Data Interpretation Question 4:
Comprehension:
Read the given passage and answer the questions that follow
The following table has the number of enrolled students for a particular course and year.
Total number of seats are given in brackets with respect to each course.
Year |
Number of Enrolled Students |
|||
BTech |
MTech |
MPhil |
MBA (60) |
|
2016 | 96 | 24 | 12 | 52 |
2017 | 110 | 26 | 14 | 57 |
2018 | 108 | 25 | 13 | 54 |
2019 | 112 | 28 | 15 | 56 |
2020 | 104 | 27 | 16 | 48 |
Find out the difference between average vacant seats of M Tech and MBA for 2016-2020
Answer (Detailed Solution Below)
Data Interpretation Question 4 Detailed Solution
Given:
Year |
Number of Enrolled Students |
||||
BTech |
MTech |
MPhil |
MBA (60) |
Total (230) |
|
2016 | 96 | 24 | 12 | 52 | 180 |
2017 | 110 | 26 | 14 | 57 | 207 |
2018 | 108 | 25 | 13 | 54 | 200 |
2019 | 112 | 28 | 15 | 56 | 211 |
2020 | 104 | 27 | 16 | 48 | 195 |
Formula Used:
Total Seats = Enrolled Seats + Vacant Seats
Calculation:
Vacant Seats in MTech for 2016-2020 = (30 - 24) + (30 - 26) + (30 - 25) + (30 - 28) + (30 - 27)
Now, average vacant seats of M Tech = (6 + 4 + 5 + 2 + 3)/5
⇒ 20/5 = 4
Vacant Seats in MBA for 2016-2020 = (60 - 52) + (60 - 57) + (60 - 54) + (60 - 56) + (60 - 48)
Now, average vacant seats of M Tech = (8 + 3 + 6 + 4 + 12)/5
⇒ 33/5 = 6.6
So, the difference between average vacant seats of M Tech and MBA for 2016-2020 = 6.6 - 4 = 2.6
∴ The difference between average vacant seats of M Tech and MBA for 2016-2020 is 2.6
Data Interpretation Question 5:
The diagram shows the rate of diamonds of different sizes. Of what size is the largest diamond that can be purchased for Rs.4.5 lakh?
Answer (Detailed Solution Below)
Data Interpretation Question 5 Detailed Solution
CONCEPT:
Diamond Price vs Weight
- The price of diamonds increases linearly with the weight of the diamond, as shown by the given graph.
- The price is given in lakhs, and the weight is in carats.
- The price at Rs. 4.5 lakh corresponds to a specific carat weight based on the line equation derived from the graph.
EXPLANATION:
- The graph shows a linear relationship between the price (in lakhs) and the weight (in carats) of diamonds.
- From the graph, Rs. 5 lakh corresponds to 2.5 carats, which represents the maximum carat size for Rs. 5 lakh.
- By drawing a line at Rs. 4.5 lakh, we find that the corresponding weight is 2.25 carats, which is the largest diamond that can be purchased for Rs. 4.5 lakh.
Therefore, the largest diamond that can be purchased for Rs. 4.5 lakh is 2.25 carats.
Top Data Interpretation MCQ Objective Questions
Direction: Study the given graph and answer the question that follows.
The expenditure on Interest on Loans is by what percentage more than the expenditure on Taxes ?
Answer (Detailed Solution Below)
Data Interpretation Question 6 Detailed Solution
Download Solution PDFGiven:
Percentage of Taxes = 5
Percentage of Interest on Loans = 7.5
Calculation:
Difference between the expense of Interest on Loans and Taxes = 7.5 - 5
⇒ 2.5
∴ The required percentage = 2.5/5 × 100
⇒ 50%
Study the given graph and answer the question that follows.
In which year was the percentage increase in the revenue as compared to that in its preceding year below 6%?
Answer (Detailed Solution Below)
Data Interpretation Question 7 Detailed Solution
Download Solution PDFFormula used:
Percentage Increase = [\(\dfrac{Final\; Value- Initial \;Value}{Initial \;Value}\)] × 100
Calculation:
Increase percent in 2015 = (350 - 320)/ 320 × 100 = 30/320 × 100 = 9.37%
Increase percent in 2016 = (380 - 350)/ 350 × 100 = 30/350 × 100 = 8.57%
Increase percent in 2017 = (400 - 380)/ 380 × 100 = 20/380 × 100 = 5.26%
Decrease percent in 2018 = (400 - 280)/ 400 × 100 = 120/400 × 100 = 30%
Increase percent in 2019 = (300 - 280)/ 280 × 100 = 20/280 × 100 = 7.14%
∴ In 2017 the percentage increase in the revenue as compared to its preceding year is below 6%.
The line graph shows the production (in tonnes) and the sales (in tonnes) of a company.
What percentage (approximately) of the total production of the company is the total sales of the company in all the years together? (correct to 2 decimal places)
Answer (Detailed Solution Below)
Data Interpretation Question 8 Detailed Solution
Download Solution PDFCalculation:
Total production = (600 + 628 + 750 + 500 + 570) tones = 3048 tons
Total sales = (450 + 525 + 500 + 400 + 516) tons = 2391 tons
∴ Percentage of the total sales = 2391/3048 × 100
⇒ 78.44%
Study the given bar chart and answer the question that follows.
The bar chart shows the production of medicines by a company (in 1000 tonnes) over six years 2010 to 2015.
If in each of the following years, the percentage increase in production as compared to the previous year is taken, then the ratio for increase production of the year 2011 to increase production of year 2015 is:
Answer (Detailed Solution Below)
Data Interpretation Question 9 Detailed Solution
Download Solution PDFFormula used:
Percentage Increase = (Production of current year - Production of previous year)/ Production of Previous year × 100
Calculation:
Percentage increase in the production of medicines of the year 2011 = (60 - 40)/40 × 100 = 20/40 × 100 = 50%
Percentage increase in the production of medicines of the year 2015 = (80 - 60)/60 × 100 = 20/60 × 100 = 100/3%
∴ The required ratio = 50% : 100/3%
⇒ 1 : 2/3
⇒ 3 : 2
A company has six departments. The given bar graph shows the number of employees in each department for the years 2015 and 2018. The company added 80 new employees and fired some employees between the years 2015 and 2018. All the employees who were fired were from department C. If the employees of department C had NOT been fired, then the employee strength of department C in 2018 would have been greater by______.
Answer (Detailed Solution Below)
Data Interpretation Question 10 Detailed Solution
Download Solution PDFCalculation:
In 2015, No. of employees in all department = 20 + 40 + 50 + 70 + 80 + 30 = 290
In 2018, No. of employees in all department = 30 + 70 + 80 + 90 + 60 + 30 = 360
Difference = 360 - 290 = 70
According to question,
No of employees added = 80
Fired employees from C = 80 - 70 = 10
Strength of C in 2018 = 80 (Given)
If not fired, strength of C in 2018 = 80 + 10 = 90
Strength of department C in 2018 would have been greater by = (10/80) × 100
⇒ 12.5%
∴ Option 1 is the correct answer.
Study the histogram that shows the marks obtained by students in an examination and answer the question that follows.
By what percentage is the number of students who obtained marks between 200 and 300 more than the number of students who obtained 350 or more marks?
Answer (Detailed Solution Below)
Data Interpretation Question 11 Detailed Solution
Download Solution PDFGiven:
No of the students who obtained marks between 200 and 300
⇒ 45 + 60 = 105
No of students who obtained marks between 350 or more marks
⇒ 40 + 35 = 75
Calculation:
⇒ The required percent = (105 - 75)/75 × 100
⇒ 30/75 × 100
⇒ 40%
∴ The answer is 40%.
Study the following bar graph and answer the question that follows.
In how many years was the export more than the average for the given period?
Answer (Detailed Solution Below)
Data Interpretation Question 12 Detailed Solution
Download Solution PDFCalculation:
Average Export diamonds for 7 years = Total export / Total no of years
⇒ (7.2 + 8.5 + 9.8 + 10.9 + 11.8 + 11.5 + 12.4)/7 = 72.1/7
⇒ 10.3 crores
In the given 4 years, the export is more than the average export:
⇒ 2011 = 10.9 crores
⇒ 2012 = 11.8 crores
⇒ 2013 = 11.5 crores
⇒ 2014 = 12.4 crores
∴ The no of years where export is more than the average export is 4.
Study the given graph and answer the question that follows.
What is the ratio of the total exports in 2014 and 2017 to the total imports in 2015 and 2018?
Answer (Detailed Solution Below)
Data Interpretation Question 13 Detailed Solution
Download Solution PDFCalculation:
Sum of the imports in 2015 & 2018 = 390 + 450 = 840 crore
Sum of the exports in 2014 & 2017 = 300 + 420 = 720 crore
∴ The required ratio = 720 : 840
⇒ 6 : 7
Study the given graph and answer the following question.
The number of lecturers recruited in state A in the year 2017 was what percentage of the number of lecturers recruited in state B in the year 2019 ? (Correct to 2 decimal places)
Answer (Detailed Solution Below)
Data Interpretation Question 14 Detailed Solution
Download Solution PDFGiven:
No. of lecturers in state A in 2017 = 10
No. of lecturers in state B in 2019 = 22
Formula used:
Percentage = \(\frac{\text{Lecturer in state A}}{\text{Lecturer in state B}}\times 100\)
Calculations:
According to the formula,
⇒ Percentage = \(\frac{10}{22}\times100\) = 45.45%
⇒ Hence, No. of lecturers in state A in 2017 is 45.45% of state B in 2019
The given bar graph indicates the production of sugar (in lakh tonnes) by three different sugar companies P, Q and R from the year 2015 to 2019. Study the bar graph and answer the question that follows.
Production of sugar by companies P, Q and R from 2015 to 2019
The percentage increase in the production of sugar by company P in 2019 as compared to 2015 is:
Answer (Detailed Solution Below)
Data Interpretation Question 15 Detailed Solution
Download Solution PDFGiven:
Production of company P in 2015 = 80 lakh tonnes
Production of company P in 2019 = 120 lakh tonnes
Calculation:
∴ The required percentage increase in 2019 = (120 - 80)/80 × 100
⇒ 40/80 × 100 = 50%