Evaluate using Integration by Parts MCQ Quiz - Objective Question with Answer for Evaluate using Integration by Parts - Download Free PDF

Last updated on Apr 11, 2025

Latest Evaluate using Integration by Parts MCQ Objective Questions

Evaluate using Integration by Parts Question 1:

Comprehension:

Direction : Consider the following for the items that follow :

Let f(x) = |x2 - x - 2|

What is  equal to

  1. 2
  2. 3
  3. 4
  4. 5

Answer (Detailed Solution Below)

Option 2 : 3

Evaluate using Integration by Parts Question 1 Detailed Solution

Explanation:

Given:

f(x) =|x2 – x – 2|

= {x2- x - 2; x ∈ (-∞, -1) ∪ (2, ∞) 

      - (x-x -2 ; ∈[ -1,2]

Let I = 

 = 3

∴ Option (b) is correct.

Evaluate using Integration by Parts Question 2:

Comprehension:

Direction : Consider the following for the items that follow :

Let f(x) = |x2 - x - 2|

What is  equal to

  1. 0
  2. 1
  3. 5/3
  4. 10/3

Answer (Detailed Solution Below)

Option 4 : 10/3

Evaluate using Integration by Parts Question 2 Detailed Solution

Explanation:

Given:

f(x) =|x2 – x – 2|.

= {x2 – x – 2; x ∈ (-∞ –1) ∪  (2,∞ ) – (x2 – x – 2); x ∈ [–1, 2]

Let I = - 

= - 

∴ Option (d) is correct

Evaluate using Integration by Parts Question 3:

The value of is?

Answer (Detailed Solution Below) 2

Evaluate using Integration by Parts Question 3 Detailed Solution

Calculation

 = 2

Evaluate using Integration by Parts Question 4:

Comprehension:

Consider the following for the items that follow:

Let 

What is  equal to ?

  1. ln(8√e)
  2. ln(4√e)
  3. ln 2
  4. ln 2 - 1

Answer (Detailed Solution Below)

Option 1 : ln(8√e)

Evaluate using Integration by Parts Question 4 Detailed Solution

Explanation -

Given the equation:

 ..... (i)

Substitute x with 1/x :

...... (ii)   

We now have two equations:

Let: f(x) = a and f(1/x) = b

The system of equations becomes:

3a + b = 1/x + 1
3b + a = x + 1

Multiply the first equation by 3:

9a + 3b = 3/x + 3

Subtract the second equation from the modified first equation:

9a + 3b - (3b + a) = 3/x + 3 - (x + 1)

⇒ 8a = 3/x + 3 - x - 1

⇒ 8a = 3/x - x + 2

⇒ a =

Therefore: f(x) =   

Thus, the function f(x) = 

Now  

= ln 8 + ln√e

= ln 8√e

Hence Option (1) is Correct.

Evaluate using Integration by Parts Question 5:

Comprehension:

Consider the following for the items that follow:

Let 

What is f(x) equal to ?

Answer (Detailed Solution Below)

Option 4 :

Evaluate using Integration by Parts Question 5 Detailed Solution

Explanation -

Given the equation:

 ..... (i)

Substitute x with 1/x :

...... (ii)   

We now have two equations:

Let: f(x) = a and f(1/x) = b

The system of equations becomes:

3a + b = 1/x + 1
3b + a = x + 1

Multiply the first equation by 3:

9a + 3b = 3/x + 3

Subtract the second equation from the modified first equation:

9a + 3b - (3b + a) = 3/x + 3 - (x + 1)

⇒ 8a = 3/x + 3 - x - 1

⇒ 8a = 3/x - x + 2

⇒ a =

Therefore: f(x) =   

Thus, the function f(x) =   

Top Evaluate using Integration by Parts MCQ Objective Questions

Answer (Detailed Solution Below)

Option 1 : 1

Evaluate using Integration by Parts Question 6 Detailed Solution

Download Solution PDF

Concept:

Integration by parts: Integration by parts is a method to find integrals of products

The formula for integrating by parts is given by;

⇒ ∫ uv dx = u(x) ∫ v(x) dx - ∫ [u'(x) ∫ v(x) dx] dx

Where u is the function u(x) and v is the function v(x), and is chosen by following ILATE rule.

ILATE Rule: Usually, the preference order of this rule is based on some functions such as Inverse, Logarithm, Algebraic, Trigonometric and Exponent.

Calculation:

Given:

Let I = 

Applying by parts rule, we get

I = (e - 0) - (e - 1)

I = 1

Hence the required value of integration is 1.

Answer (Detailed Solution Below)

Option 3 : 1

Evaluate using Integration by Parts Question 7 Detailed Solution

Download Solution PDF

Concept:

Modulus Function:

A modulus function is a function which gives the absolute value of a number or variable.

Formula Used:

Calculation:

We have,

⇒ I = 

⇒ 1 - x

⇒ I = 

⇒ I = 

⇒ I =  - 

⇒ I = 

⇒ I = 

⇒ I = 1

∴ The value of  is 1.

The value of  is

  1. π3 - 6π
  2. 3 - 6π
  3. 3 + 6π
  4. π3 + 6π

Answer (Detailed Solution Below)

Option 1 : π3 - 6π

Evaluate using Integration by Parts Question 8 Detailed Solution

Download Solution PDF

Concept:

Integration by parts: Integration by parts is a method to find integrals of products

  • The formula for integrating by parts is given by,
  • ∫u v dx = u∫v dx −∫u' (∫v dx) dx

Where u is the function u(x) and v is the function v(x)

ILATE Rule: Usually, the preference order of this rule is based on some functions such as Inverse, Logarithm, Algebraic, Trigonometric and Exponent.

Calculation:

Let I = 

Apply by parts rule, we get

= π3 - 6π

Hence, option (1) is correct.

Answer (Detailed Solution Below)

Option 2 :

Evaluate using Integration by Parts Question 9 Detailed Solution

Download Solution PDF

Concept:

1. Integration by parts: Integration by parts is a method to find integrals of products

The formula for integrating by parts is given by;

 , Where u is the function u(x) and v is the function v(x)

 

2. ILATE Rule: Usually, the preference order of this rule is based on some functions such as Inverse, Logarithm, Algebraic, Trigonometric and Exponent.

 

Calculation:

Let I = 

Apply by parts rule,

Answer (Detailed Solution Below)

Option 1 : 3π 

Evaluate using Integration by Parts Question 10 Detailed Solution

Download Solution PDF

Concept:

Integration by parts: Integration by parts is a method to find integrals of products

The formula for integrating by parts is given by;

  

Where u is the function u(x) and v is the function v(x)

 

ILATE Rule: Usually, the preference order of this rule is based on some functions such as Inverse, Logarithm, Algebraic, Trigonometric and Exponent.

 

Calculation:

First we will calculate the integration without the limits.

Let us consider  .

On differentiating u on both sides we get,

  .

Therefore, we integrate the given function as follows:

Now as the given integral is definite we will remove the constant of integration and put the limits.

Therefore, .

The value of the quantity P where  is equal to

  1. 0
  2. 1
  3. e
  4. 1/e

Answer (Detailed Solution Below)

Option 2 : 1

Evaluate using Integration by Parts Question 11 Detailed Solution

Download Solution PDF

Concept:

Calculation:

Given:

Applying limits,

= [1 × e1 – e1] – [0 × e0 – e0]

= [e1 – e1] – [0 - 1]

= 1

Answer (Detailed Solution Below)

Option 2 :

Evaluate using Integration by Parts Question 12 Detailed Solution

Download Solution PDF

Comprehension:

Direction : Consider the following for the items that follow :

Let f(x) = |x2 - x - 2|

What is  equal to

  1. 0
  2. 1
  3. 5/3
  4. 10/3

Answer (Detailed Solution Below)

Option 4 : 10/3

Evaluate using Integration by Parts Question 13 Detailed Solution

Download Solution PDF

Explanation:

Given:

f(x) =|x2 – x – 2|.

= {x2 – x – 2; x ∈ (-∞ –1) ∪  (2,∞ ) – (x2 – x – 2); x ∈ [–1, 2]

Let I = - 

= - 

∴ Option (d) is correct

Comprehension:

Direction : Consider the following for the items that follow :

Let f(x) = |x2 - x - 2|

What is  equal to

  1. 2
  2. 3
  3. 4
  4. 5

Answer (Detailed Solution Below)

Option 2 : 3

Evaluate using Integration by Parts Question 14 Detailed Solution

Download Solution PDF

Explanation:

Given:

f(x) =|x2 – x – 2|

= {x2- x - 2; x ∈ (-∞, -1) ∪ (2, ∞) 

      - (x-x -2 ; ∈[ -1,2]

Let I = 

 = 3

∴ Option (b) is correct.

Evaluate using Integration by Parts Question 15:

What is  equal to?

  1. 1
  2. -1
  3. 0
  4. e

Answer (Detailed Solution Below)

Option 1 : 1

Evaluate using Integration by Parts Question 15 Detailed Solution

Concept:

Integration by parts: Integration by parts is a method to find integrals of products

The formula for integrating by parts is given by;

⇒ ∫ uv dx = u(x) ∫ v(x) dx - ∫ [u'(x) ∫ v(x) dx] dx

Where u is the function u(x) and v is the function v(x), and is chosen by following ILATE rule.

ILATE Rule: Usually, the preference order of this rule is based on some functions such as Inverse, Logarithm, Algebraic, Trigonometric and Exponent.

Calculation:

Given:

Let I = 

Applying by parts rule, we get

I = (e - 0) - (e - 1)

I = 1

Hence the required value of integration is 1.

Hot Links: teen patti master 2024 teen patti rummy 51 bonus teen patti online